In this chapter we compute the repeating sequence and its length for
circulating fraction of 1/p where p is prime up to 100 except 2 and 5.
For example,
1/7 = 0.[142857], length=6
1/11 = 0.[09], length=2
1/13 = 0.[76923], length=6
...
Formal notation of repeating decimal is to put a dot on the begin and end of repeating letter. But it is inconvenient for HTML notation, so in this chapter we donote as above, that is, locating repeating decimals between [ ] .
When we compute 1 divede by 7 by hand, we do as follows;
1/7=0 ... 1
put "0" at the right of "1", compute 10/7
10/7=1 ... 3
put "0" at the right of "3", compute 30/7
......
repeating the procedure that "put 0 at the right of previous remainder and divide by 7".
When the remainder is equal to "1", the next circulation starts.
The remainders dividing by p are,
1, 2, ... , p-1
so the length of repeating decimals is at most p-1.
10 ' cycle 20 A=1:P=7 30 B=A*10\P:A=res:print B;:if A<>1 then 30
We compute the repeating sequence and its length for
circulating fraction of 1/p where p is prime up to 100 except 2 and 5.
5 ' cycle_p 10 for I=1 to 25:N=prm(I):if or{N=2,N=5} then 100 20 int "n=";N 30 A=1:Length=0 40 B=A*10\N:A=res:print B;:inc Length:if A<>1 then 40 50 print:print Length 60 next I
Repeating sequences of 1/p for prime between 2 ≤ p < 100 are here.
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