For furthur computation, we may try,
But these simple modification cannot conquer the solution for n=564,
x = 122 44200 50100 02877 81163 51171 17995 21361 35134 91867 (48 digits)
y = -3460 69586 84255 04865 64589 22621 88752 08971 30654 24460 (49 digits)
z = 74807 19101 53025 27837 94583 60171 46464 94820 59055 28060 (50 digits)
So, let's consult to the Bremner's paper.
Bremner's method is,
Given Diophantine equation n=(x+y+z)(1/x+1/y+1/z) is equivalent under the following
birational map,
X = -4(yz+zx+xy)/z2
Y = 2(X-4n)y/z-(n-1)X
to the elliptic curve E,
E : Y2 = X(X2+(n2-6n-3)X+16n)
The map from the elliptic curve to the diophantine equation is,
x,y/z = {±Y-(n-1)X}/2(4n-X)
So, searching the rational point on the elliptic curve E,
transform with the above birational map,
and find out the solution of n=(x+y+z)(1/x+1/y+1/z).
The computation results with Cremona's mwrank are below.
solutions for -500 ≤ n ≤ -1
solutions for 1 ≤ n ≤ 500
Now we get;
n = -100 : (x,y,z) = (4450012553, 219887106322, -663397965750)
n = 94 : (x,y,z) = (571064, -1799160, 79045681)
n | x | y | z |
---|---|---|---|
-(k2-5) (k≥3) | k+1 | k-1 | -k(k2-1)/2 |
-(k2+3) (k≥3) | (k3+3k2+4k+4)/2 | (k3-3k2+4k-4)/2 | -k(k4+3k2+4)/4 |
-(k-1)(k+2) (k≥3) | 1 | k | -k(k+1) |
v4k+8 | u2k-1 | u2k+1 | u2k-1v2ku2k+1 |
u2k2 | -u2k-1 | u2k+1 | u2k-1u2ku2k+1 |
uk and vk are Fibonacci number and Lucas number, respectively. The definitions are following;
Fibonacci number uk :
u1=1, u2=1, uk+1=uk+uk-1
Lucas number vk :
v1=1, v2=3, vk+1=vk+vk-1
For two parameter diophantine equation n=(x+y)(1/x+1/y),
the solutions are only the cases
n=0, 4.
And for four parameter diophantine equation n=(x+y+z+w)(1/x+1/y+1/z+1/w),
there is a parametrized solution such that
x = m2+m+1
y = m(m+1)(n-1)
z = (m+1)(n-1)
w = -m(n-1)
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